6[x+3]=2[3x+1]

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Solution for 6[x+3]=2[3x+1] equation:


Simplifying
6[x + 3] = 2[3x + 1]

Reorder the terms:
6[3 + x] = 2[3x + 1]
[3 * 6 + x * 6] = 2[3x + 1]
[18 + 6x] = 2[3x + 1]

Reorder the terms:
18 + 6x = 2[1 + 3x]
18 + 6x = [1 * 2 + 3x * 2]
18 + 6x = [2 + 6x]

Add '-6x' to each side of the equation.
18 + 6x + -6x = 2 + 6x + -6x

Combine like terms: 6x + -6x = 0
18 + 0 = 2 + 6x + -6x
18 = 2 + 6x + -6x

Combine like terms: 6x + -6x = 0
18 = 2 + 0
18 = 2

Solving
18 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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